Hive Solution
3.Hive Solution
-- **Example 1:**
create table leetcode.ex_2010_s1 as
SELECT
employee_id,
experience,
salary,
salary_sum,
(70000 - salary_sum) as balance
FROM
(select *,sum(salary)over(ORDER BY rn) as salary_sum
from (select *, ROW_NUMBER() OVER( ORDER BY salary) AS rn from leetcode.ex_2010_candidates_1
where experience = 'Senior' ) a
) b
;
create table leetcode.ex_2010_j1 as
SELECT
t1.employee_id,
t1.experience,
t1.salary,
t1.salary_sum,
(t2.balance_min_senior - t1.salary_sum) as balance
FROM
( select 'id' as id,*,sum(salary)over(ORDER BY rn) as salary_sum
from (select *, ROW_NUMBER() OVER(ORDER BY salary) AS rn from leetcode.ex_2010_candidates_1
where experience = 'Junior' ) a
) t1
join (select 'id' as id, coalesce(min(balance),70000) as balance_min_senior from leetcode.ex_2010_s1
where balance >0
) t2 ON t1.id=t2.id
;
select employee_id
from leetcode.ex_2010_s1 where balance>=0
UNION
select employee_id
from leetcode.ex_2010_j1 where balance>=0
;
-- **Example 2:**
create table leetcode.ex_2010_s2 as
SELECT
employee_id,
experience,
salary,
salary_sum,
(70000 - salary_sum) as balance
FROM
(select *,sum(salary)over(ORDER BY rn) as salary_sum
from (select *, ROW_NUMBER() OVER( ORDER BY salary) AS rn from leetcode.ex_2010_candidates_2
where experience = 'Senior' ) a
) b
;
create table leetcode.ex_2010_j2 as
SELECT
t1.employee_id,
t1.experience,
t1.salary,
t1.salary_sum,
(t2.balance_min_senior - t1.salary_sum) as balance
FROM
( select 'id' as id,*,sum(salary)over(ORDER BY rn) as salary_sum
from (select *, ROW_NUMBER() OVER(ORDER BY salary) AS rn from leetcode.ex_2010_candidates_2
where experience = 'Junior' ) a
) t1
join (select 'id' as id, coalesce(min(balance),70000) as balance_min_senior from leetcode.ex_2010_s2
where balance >0
) t2 ON t1.id=t2.id
;
select employee_id
from leetcode.ex_2010_s2 where balance>=0
UNION
select employee_id
from leetcode.ex_2010_j2 where balance>=0
;
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