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Hands-On Leetcode Database Solution with Hive SQL
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  • INTRODUCTION
    • About This Book
    • 作者簡介
  • Exercise 1:185.Department Top Three Salaries
    • Hive Solution
  • Exercise 2:262. Trips and Users
    • Hive Solution
  • Exercise 3:569.Median Employee Salary
    • Hive Solution
  • Exercise 4:571.Find Median Given Frequency of Numbers
    • Hive Solution
  • Exercise 5:579.Find Cumulative Salary Of An Employee Problem
    • Hive Solution
  • Exercise 6:601.Human Traffic of Stadium
    • Hive Solution
  • Exercise 7:615.Average Salary: Departments VS Company
    • Hive Solution
  • Exercise 8:618.Students Report By Geography
    • Hive Solution
  • Exercise 9:1097.Game Play Analysis V
    • Hive Solution
  • Exercise 10:1127.User Purchase Platform
    • Hive Solution
  • Exercise 11:1159.Market Analysis II
    • Hive Solution
  • Exercise 12:1194.Tournament Winners
    • Hive Solution
  • Exercise 13:1225.Report Contiguous Dates
    • Hive Solution
  • Exercise 14:1336.The number of transactions per visit
    • Hive Solution
  • Exercise 15:1369.Get The Second Most Recent Activity
    • Hive Solution
  • Exercise 16:1384.Total Sales Amount by Year
    • Hive Solution
  • Exercise 17:1412.Find the Quiet Students in All Exams
    • Hive Solution
  • Exercise 18:1479. Sales by Day of the Week
    • Hive Solution
  • Exercise 19:1635. Hopper Company Queries I
    • Hive Solution
  • Exercise 20:1645. Hopper Company Queries II
    • Hive Solution
  • Exercise21 :1651. Hopper Company Queries III
    • Hive Solution
  • Exercise 22:1767.Find the Subtasks That Did Not Execute
    • Hive Solution
  • Exercise 23:1892.Page Recommendations II
    • Hive Solution
  • Exercise 24:1917.Leetcodify Friends Recommendations
    • Hive Solution
  • Exercise 25:1919.Leetcodify Similar Friends
    • Hive Solution
  • Exercise 26:1972.First and Last Call On the Same Day
    • Hive Solution
  • Exercise 27:2004.The Number of Seniors and Juniors to Join the Company
    • Hive Solution
  • Exercise 28:2010.The Number of Seniors and Juniors to Join the Company II
    • Hive Solution
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  • 1 Description
  • 2 Create Table and insert into values

Exercise 2:262. Trips and Users

1 Description

Table: Trips

+-------------+----------+
| Column Name | Type     |
+-------------+----------+
| id          | int      |
| client_id   | int      |
| driver_id   | int      |
| city_id     | int      |
| status      | enum     |
| request_at  | date     |     
+-------------+----------+
id is the primary key for this table.
The table holds all taxi trips. Each trip has a unique id, while client_id and driver_id are foreign keys to the users_id at the Users table.
Status is an ENUM type of ('completed', 'cancelled_by_driver', 'cancelled_by_client').

Table: Users

+-------------+----------+
| Column Name | Type     |
+-------------+----------+
| users_id    | int      |
| banned      | enum     |
| role        | enum     |
+-------------+----------+
users_id is the primary key for this table.
The table holds all users. Each user has a unique users_id, and role is an ENUM type of ('client', 'driver', 'partner').
banned is an ENUM type of ('Yes', 'No').

The cancellation rate is computed by dividing the number of canceled (by client or driver) requests with unbanned users by the total number of requests with unbanned users on that day.

Write a SQL query to find the cancellation rate of requests with unbanned users (both client and driver must not be banned) each day between "2013-10-01" and "2013-10-03". Round Cancellation Rate to two decimal points.

Return the result table in any order.

The query result format is in the following example.

Example 1:

Input: 
Trips table:
+----+-----------+-----------+---------+---------------------+------------+
| id | client_id | driver_id | city_id | status              | request_at |
+----+-----------+-----------+---------+---------------------+------------+
| 1  | 1         | 10        | 1       | completed           | 2013-10-01 |
| 2  | 2         | 11        | 1       | cancelled_by_driver | 2013-10-01 |
| 3  | 3         | 12        | 6       | completed           | 2013-10-01 |
| 4  | 4         | 13        | 6       | cancelled_by_client | 2013-10-01 |
| 5  | 1         | 10        | 1       | completed           | 2013-10-02 |
| 6  | 2         | 11        | 6       | completed           | 2013-10-02 |
| 7  | 3         | 12        | 6       | completed           | 2013-10-02 |
| 8  | 2         | 12        | 12      | completed           | 2013-10-03 |
| 9  | 3         | 10        | 12      | completed           | 2013-10-03 |
| 10 | 4         | 13        | 12      | cancelled_by_driver | 2013-10-03 |
+----+-----------+-----------+---------+---------------------+------------+
Users table:
+----------+--------+--------+
| users_id | banned | role   |
+----------+--------+--------+
| 1        | No     | client |
| 2        | Yes    | client |
| 3        | No     | client |
| 4        | No     | client |
| 10       | No     | driver |
| 11       | No     | driver |
| 12       | No     | driver |
| 13       | No     | driver |
+----------+--------+--------+
Output: 
+------------+-------------------+
| Day        | Cancellation Rate |
+------------+-------------------+
| 2013-10-01 | 0.33              |
| 2013-10-02 | 0.00              |
| 2013-10-03 | 0.50              |
+------------+-------------------+
Explanation: 
On 2013-10-01:
  - There were 4 requests in total, 2 of which were canceled.
  - However, the request with Id=2 was made by a banned client (User_Id=2), so it is ignored in the calculation.
  - Hence there are 3 unbanned requests in total, 1 of which was canceled.
  - The Cancellation Rate is (1 / 3) = 0.33
On 2013-10-02:
  - There were 3 requests in total, 0 of which were canceled.
  - The request with Id=6 was made by a banned client, so it is ignored.
  - Hence there are 2 unbanned requests in total, 0 of which were canceled.
  - The Cancellation Rate is (0 / 2) = 0.00
On 2013-10-03:
  - There were 3 requests in total, 1 of which was canceled.
  - The request with Id=8 was made by a banned client, so it is ignored.
  - Hence there are 2 unbanned request in total, 1 of which were canceled.
  - The Cancellation Rate is (1 / 2) = 0.50

2 Create Table and insert into values

create table if not exists leetcode.ex_262_trips
(
 id string, 
  client_id string, 
  driver_id string, 
  city_id string, 
  status string, 
  request_at date
)  stored as orc ;

INSERT INTO table leetcode.ex_262_trips  VALUES
( '1'  , '1'         , '10'        , '1'       , 'completed'           , '2013-10-01' ),
( '2'  , '2'         , '11'        , '1'       , 'cancelled_by_driver' , '2013-10-01' ),
( '3'  , '3'         , '12'        , '6'       , 'completed'           , '2013-10-01' ),
( '4'  , '4'         , '13'        , '6'       , 'cancelled_by_client' , '2013-10-01' ),
( '5'  , '1'         , '10'        , '1'       , 'completed'           , '2013-10-02' ),
( '6'  , '2'         , '11'        , '6'       , 'completed'           , '2013-10-02' ),
( '7'  , '3'         , '12'        , '6'       , 'completed'           , '2013-10-02' ),
( '8'  , '2'         , '12'        , '12'      , 'completed'           , '2013-10-03' ),
( '9'  , '3'         , '10'        , '12'      , 'completed'           , '2013-10-03' ),
( '10' , '4'         , '13'        , '12'      , 'cancelled_by_driver' , '2013-10-03' )

create table if not exists leetcode.ex_262_users
(users_id string, 
 banned string, 
 role string
) stored as orc;

INSERT INTO table leetcode.ex_262_users  VALUES
('1'        , 'No'     , 'client' ),
('2'        , 'Yes'    , 'client' ),
('3'        , 'No'     , 'client' ),
('4'        , 'No'     , 'client' ),
('10'       , 'No'     , 'driver' ),
('11'       , 'No'     , 'driver' ),
('12'       , 'No'     , 'driver' ),
('13'       , 'No'     , 'driver' )

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