Exercise 3：569.Median Employee Salary
The
Employee table holds all employees. The employee table has three columns: Employee Id, Company Name, and Salary.+-----+------------+--------+
|Id | Company | Salary |
+-----+------------+--------+
|1 | A | 2341 |
|2 | A | 341 |
|3 | A | 15 |
|4 | A | 15314 |
|5 | A | 451 |
|6 | A | 513 |
|7 | B | 15 |
|8 | B | 13 |
|9 | B | 1154 |
|10 | B | 1345 |
|11 | B | 1221 |
|12 | B | 234 |
|13 | C | 2345 |
|14 | C | 2645 |
|15 | C | 2645 |
|16 | C | 2652 |
|17 | C | 65 |
+-----+------------+--------+
Write a SQL query to find the median salary of each company. Bonus points if you can solve it without using any built-in SQL functions.
+-----+------------+--------+
|Id | Company | Salary |
+-----+------------+--------+
|5 | A | 451 |
|6 | A | 513 |
|12 | B | 234 |
|9 | B | 1154 |
|14 | C | 2645 |
+-----+------------+--------+
create table if not exists leetcode.ex_569_employee
(
id string,
company string,
salary int
) stored as orc ;
INSERT INTO table leetcode.ex_569_employee VALUES
('1' ,'A' ,'2341' ),
('2' ,'A' ,'341' ),
('3' ,'A' ,'15' ),
('4' ,'A' ,'15314' ),
('5' ,'A' ,'451' ),
('6' ,'A' ,'513' ),
('7' ,'B' ,'15' ),
('8' ,'B' ,'13' ),
('9' ,'B' ,'1154' ),
('10' ,'B' ,'1345' ),
('11' ,'B' ,'1221' ),
('12' ,'B' ,'234' ),
('13' ,'C' ,'2345' ),
('14' ,'C' ,'2645' ),
('15' ,'C' ,'2645' ),
('16' ,'C' ,'2652' ),
('17' ,'C' ,'65' )
In statistics and probability theory, the median is the value separating the higher half from the lower half of a data sample. The Median is the "middle" of a sorted list of numbers.
This problem requires we find which employee's salary is median and what salary is for each company, NOT calculating the company's median salary.
Last modified 11mo ago