+---------------+---------+
| Column Name | Type |
+---------------+---------+
| order_id | int |
| customer_id | int |
| order_date | date |
| item_id | varchar |
| quantity | int |
+---------------+---------+
(ordered_id, item_id) is the primary key for this table.
This table contains information of the orders placed.
order_date is the date when item_id was ordered by the customer with id customer_id.
Table: Items
+---------------------+---------+
| Column Name | Type |
+---------------------+---------+
| item_id | varchar |
| item_name | varchar |
| item_category | varchar |
+---------------------+---------+
item_id is the primary key for this table.
item_name is the name of the item.
item_category is the category of the item.
You are the business owner and would like to obtain a sales report for category items and day of the week.
Write an SQL query to report how many units in each category have been ordered on each day of the week.
Return the result table ordered by category.
The query result format is in the following example:
Orders table:
+------------+--------------+-------------+--------------+-------------+
| order_id | customer_id | order_date | item_id | quantity |
+------------+--------------+-------------+--------------+-------------+
| 1 | 1 | 2020-06-01 | 1 | 10 |
| 2 | 1 | 2020-06-08 | 2 | 10 |
| 3 | 2 | 2020-06-02 | 1 | 5 |
| 4 | 3 | 2020-06-03 | 3 | 5 |
| 5 | 4 | 2020-06-04 | 4 | 1 |
| 6 | 4 | 2020-06-05 | 5 | 5 |
| 7 | 5 | 2020-06-05 | 1 | 10 |
| 8 | 5 | 2020-06-14 | 4 | 5 |
| 9 | 5 | 2020-06-21 | 3 | 5 |
+------------+--------------+-------------+--------------+-------------+
Items table:
+------------+----------------+---------------+
| item_id | item_name | item_category |
+------------+----------------+---------------+
| 1 | LC Alg. Book | Book |
| 2 | LC DB. Book | Book |
| 3 | LC SmarthPhone | Phone |
| 4 | LC Phone 2020 | Phone |
| 5 | LC SmartGlass | Glasses |
| 6 | LC T-Shirt XL | T-Shirt |
+------------+----------------+---------------+
Result table:
+------------+-----------+-----------+-----------+-----------+-----------+-----------+-----------+
| Category | Monday | Tuesday | Wednesday | Thursday | Friday | Saturday | Sunday |
+------------+-----------+-----------+-----------+-----------+-----------+-----------+-----------+
| Book | 20 | 5 | 0 | 0 | 10 | 0 | 0 |
| Glasses | 0 | 0 | 0 | 0 | 5 | 0 | 0 |
| Phone | 0 | 0 | 5 | 1 | 0 | 0 | 10 |
| T-Shirt | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
+------------+-----------+-----------+-----------+-----------+-----------+-----------+-----------+
On Monday (2020-06-01, 2020-06-08) were sold a total of 20 units (10 + 10) in the category Book (ids: 1, 2).
On Tuesday (2020-06-02) were sold a total of 5 units in the category Book (ids: 1, 2).
On Wednesday (2020-06-03) were sold a total of 5 units in the category Phone (ids: 3, 4).
On Thursday (2020-06-04) were sold a total of 1 unit in the category Phone (ids: 3, 4).
On Friday (2020-06-05) were sold 10 units in the category Book (ids: 1, 2) and 5 units in Glasses (ids: 5).
On Saturday there are no items sold.
On Sunday (2020-06-14, 2020-06-21) were sold a total of 10 units (5 +5) in the category Phone (ids: 3, 4).
There are no sales of T-Shirt.
2.Create Table and insert into values
create table if not exists leetcode.ex_1479_orders
(order_id string,
customer_id string,
order_date date,
item_id string,
quantity int
) stored as orc ;
INSERT INTO table leetcode.ex_1479_orders VALUES
('1','1','2020-06-01','1','10'),
('2','1','2020-06-08','2','10'),
('3','2','2020-06-02','1','5'),
('4','3','2020-06-03','3','5'),
('5','4','2020-06-04','4','1'),
('6','4','2020-06-05','5','5'),
('7','5','2020-06-05','1','10'),
('8','5','2020-06-14','4','5'),
('9','5','2020-06-21','3','5')
;
create table if not exists leetcode.ex_1479_items
(item_id string,
item_name string,
item_category string
) stored as orc ;
INSERT INTO table leetcode.ex_1479_items VALUES
('1','LC Alg. Book','Book'),
('2','LC DB. Book','Book'),
('3','LC SmarthPhone','Phone'),
('4','LC Phone 2020','Phone'),
('5','LC SmartGlass','Glasses'),
('6','LC T-Shirt XL','T-Shirt')
;
There is no function for the day of the week in Hive (SQL is dayofweek()), but it can be implemented with datediff() and pmod()
方法：pmod(datediff('date', '2012-01-01'), 7)
2012-01-01 is Sunday, the above function returns "0-6" ("0-6" means "Sunday-Saturday" respectively)